using identities evaluate 103 × 98

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Textbook Solutions 19009. Using identities, evaluate. Expert Answer: Answered by | 4th Jun, 2014, 03:23: PM. The algebraic identities are verified using the substitution method. Expert Answer: Answered by | 4th Jun, 2014, 03:23: PM. Evaluate each of the following using identities: (i) (399)^2 (ii) (0.98)^2 (iii) 991 x 1009 (iv) 117 x 83 asked Feb 11 in Algebraic Expressions by ShasiRaj ( 62.4k points) algebraic identities Ex 2.5, 7 Evaluate the following using suitable identities: (i) (99)3 We write 99 = 100 – 1 (99)3 = (100 − 1)3 Using (a – b)3 = a3 – b3 – 3ab(a – b) Where a = 100 & b = 1 = (100)3 − (1)3 − 3(100) (1) (100 − 1) = 1000000 − 1 − 300(99) = 1000000 − 1 − 29700 = 970299 Ex 2.5, 7 Eva (ii) Two terms like 4mn 2 are: 6mn 2 and –2n 2 m. (iii) Two terms like 21 are: 51 and -7b. By using identity evaluate the following: 73 – 103 + 33 . Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities Last updated at Dec. 24, 2018 by Teachoo Subscribe to our Youtube Channel - https://you.tube/teachoo Textbook Solutions 1231. Using suitable identity, evaluate the following. All Questions Ask Doubt (2/3m+3/2n) ² If x cube + 2 square equal to a square x 6 plus x cube + 4, then find a. Expansion of algebraic expressions using identities. Solution: 71 2 = (70+1) 2. Related Videos. Concept Notes & Videos 257. (i) 71 2 (ii) 99 2 (iii) 102 2 (iv) 998 2 (v) 5.2 2 (vi) 297 x 303 (vii) 78 x 82 (viii) 8.9 2 (ix) 1.05 x 9.5 Solution: Ex 9.5 Class 8 Maths Question 7. ∵ 297 = 300 - 3 and 303 = 300 + 3 ∴ 297 x 303 = (300 - 3) (300 + 3) = (300)2 - (3)2 [Using (a + b)(a - b) = a2 -b2] = 90000 - 9 = 89991 = a 2 – b 2 + b 2 – c 2 + c 2 – a 2 = 0 = RHS. Learn and explore the use of algebraic identities or formulas to evaluate the numerical expressions with this series of printable worksheets. Evaluate using suitable identities. Using formula (a + b) 2 = a 2 + b 2 + 2ab = 70 2 + 1 2 + 140 = 4900 + 140 +1 = 5041 (ii) 99². asked Sep 13, 2018 in Class IX Maths by muskan15 (-3,443 points) polynomials. (103)^2, Evaluate using suitable identities. Advertisement Remove all ads. Best answer. (i) 71 2 (ii) 99 2 (iii) 102 2 (iv) 998 2 (v) 5.2 2 (vi) 297 x 303 (vii) 78 x 82 (viii) 8.9 2 (ix) 1.05 x 9.5 Solution: Ex 9.5 Class 8 Maths Question 7. To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW Evaluate using suitable identity (ii) `97 xx 103` Try squaring 1013. Use Identities to Evaluate : (97)2 . Expansion of algebraic expressions using identities. Share with your friends. answered Aug 4, 2020 by Dev01 (51.7k points) selected Aug 5, 2020 by Rani01 . CISCE ICSE Class 9. 98 x 103, Evaluate using suitable identities. Related Videos. (103) 2 = (100 + 3) 2 = 100 2 + 2 × 100 × 3 + 3 2 (Using Identity I) = 10000 + 600 + 9 = 10609. using identity evaluate 107 - Mathematics - TopperLearning.com | o5uhf4ybb Evaluate using suitable identities. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. ` (103)^3` BSEB matric hall ticket 2021 has been released, know steps to download. Using factor theorem,show that (x-y) is a factor of x(y(square) - z(square)) + y(z(square) - x(square)) + z(x(square) - y(square) ). Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities Last updated at Dec. 24, 2018 by Teachoo Subscribe to our Youtube Channel - https://you.tube/teachoo Using identities, evaluate : . 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, .. Advertisement Remove all ads. Evaluate the following using identities: (0.98) 2 Solution Show Solution. 10 ; oops the answer is 1092727, in third step 3^3 will be 27. 10.1 x 10.2, Evaluate using suitable identities. All the solution has been made by experts in detail. Evaluate each of the following using identities: (i) (399)^2 (ii) (0.98)^2 (iii) 991 x 1009 (iv) 117 x 83 asked Aug 4, 2018 in Mathematics by Sonu khan ( 35.6k points) algebraic identities 102 × 106. algebraic expressions; class-8; Share It On Facebook Twitter Email. answered Aug 4, 2020 by Dev01 (51.7k points) selected Aug 5, 2020 by Rani01 . Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Click hereto get an answer to your question ️ Using suitable identity, evaluate (i) \( 102 \times 98 ( \) (ii) \( ) ( 2 x - 3 ) \) (iii) \( ( 4 y + 3 ) ( 4 y \) Using factor theorem, factorise the polynomial x3 + x2 - 4x - 4. answered Mar 31, 2020 by Sunil01 (67.6k points) selected Apr 2, 2020 by Mohini01 . Yes, you can always get a decimal approximation with your calculator, but it's good to learn the logic of using the identities, so you can exercise your skills at pattern-finding and -matching. Best answer. Question Papers 10. Paiye sabhi sawalon ka Video solution sirf photo … using the identities evaluate 1)94 * 94 - 6 * 6/ (94 -6) 2) 9 2 *8 8 3) 103 * 98 4) 103 (square) - Math - Algebraic Expressions and Identities Using suitable identity, evaluate the following. Using suitable identity evaluate (103) 3. 1 answer. Using identities, evaluate : . We may also directly multiply 103 by 103 and get the answer. (2) Evaluate the following by using identities: (i) 98 3 (ii) 1001 3 Solution (3) If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x 2 + y 2 + z 2 Solution (4) Find 27a 3 + 64b 3, if 3a + 4b = 10 and ab = 2. 1 Answer. Example 17 Evaluate 105 × 106 without multiplying directly. 1 Answer +1 vote . Syllabus. Important Solutions 3. Evaluate:(104)cube using a suitable identity. Ask questions, doubts, problems and we will help you. (i) 103 3 (ii) 101 x 102 (iii) 999 2 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. Evaluate each of the following by using identities: (i)`103\ xx\ 97` (ii) `103\ xx\ 103` (iii) `(97)^2` Evaluate each of the following by using identities: (i)`103\ xx\ 97` (ii) `103\ xx\ 103` (iii) `(97)^2` Doubtnut is better on App. Share with your friends. 102 × 106 = (100 + 2) (100 + 6) This is in the form. Using suitable identity, evaluate the following. Share 4 . Evaluate 105 x 108 without multiplying directly. NCERT Solutions; Board Paper Solutions; Ask & Answer; School Talk; Login; GET APP; Login Create Account. Syllabus. Question Bank Solutions 15191. Using suitable identity, evaluate the following. Class-9 » Math. Evaluate using identities:- (a) 103 X 97 (b) (0 99)(0 99) (c) 105 X 105 X 105 - Math - Polynomials Textbook Solutions 1231. If p (x) = x2 – 4x + 3, then evaluate p(2) – p (-1) + p (1/2). 1 Answer +1 vote . Question 6. Evaluate the following using suitable identities (98)3 - Math - Polynomials. Concept Notes & Videos 256. Expand using suitable identity (-2x + 5y - 3z) to the whole square. Evaluate using suitable identities. Best answer. (i) 712 (ii) 992 (iii) (v) 5.22 (vi) 297 × 303 (vii) (ix) 1.05 × 9.5 7. we have followed CBSE evaluation pattern where you can score on steps and not just on final answer. Using identities evaluate 99×103. Solution (5) Find x 3 - y 3, if x - y = 5 and xy = 14 Solution (i) 1033           (ii) 101 x 102       (iii) 9992 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. (i) 103 3 (ii) 101 x 102 (iii) 999 2 Firstly adjust the given number into two number such that one is a multiple of 10 and use the proper identity. 1000000+9+90000+2700. Get NCERT Solution class 8 Maths Chapter 9 Algebraic Expressions and Identities Exercise-9.5. 0 votes . ∵ 78 = 80 - 2 and 82 = 80 + 2 ∴ 78 x 82 = (80 - 2) (80 + 2) = (80)2 - (2)2 [Using (a + b)(a - b) = a2 -b2] = 6400 - 4 = 6396 (i) Two terms like 7xy are: –3xy and 8xy. Using suitable identity, evaluate the following. Using suitable identity, evaluate the following. 1092709. thumbs up if u understood!! Using identity evaluate: 107 x 103. Polynomials. (103) 2. algebraic expressions; factorisation; class-8; Share It On Facebook Twitter Email. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, .. Available for CBSE, ICSE and State Board syllabus. Trigonometric identities like sin²θ+cos²θ=1 can be used to rewrite expressions in a different, more convenient way. Tamil Nadu Board of Secondary Education SSLC (English Medium) Class 9th. We have (0.98) 2 = [1 - 0.02] 2 = (1) 2 + (0.02) 2 - 2 x 1 x 0.02 = 1 + 0.0004 - 0.04 [∵ a = 1, b = 0.02] Using identity evaluate: 107 x 103. Use Identities to Evaluate : (97)2 - Mathematics. Tamil Nadu Board of Secondary Education SSLC (English Medium) Class 9th. Do you see that Identity (I) has given us a less tedious method than the direct method of squaring 103? Share 0 (98) 3 = (100 2) 3. evaluate using suitable identities 1 .` (99)^3` 2. Evaluate the following using suitable identities (98) 3. 101 x 103, Evaluate using suitable identities. Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM. Using Identities to Evaluate Once you've learned some trig identities , you can use them to evaluate angles exactly. Bihar board class 10 admit card 2021 latest update. Example 17 Evaluate 105 × 106 without multiplying directly. ... 103 × 98 (iv) 9.7 × 9.8. Expand using suitable identity (-2x + 5y - 3z) to the whole square. Question Bank Solutions 1231. In this method, substitute the values for the variables and perform the arithmetic operation. Advertisement Remove all ads. 9.8 x 10.2. Question Bank Solutions 1231. All Questions Ask Doubt (2/3m+3/2n) ² If x cube + 2 square equal to a square x 6 plus x cube + 4, then find a. (98)^2, Evaluate using suitable identities. Another method to verify the algebraic identity is the activity method. (i) 71². asked Jan 30, 2018 in Class IX Maths by navnit40 (-4,939 points) polynomials +1 vote. 12 ; View Full Answer (100+3)3. Evaluate using identities (a) 103×97. For example, (1-sin²θ)(cos²θ) can be rewritten as (cos²θ)(cos²θ), and then as cos⁴θ. 0 votes. Ask questions, doubts, problems and we will help you. Get a free home demo of LearnNext. By using identity evaluate the following: 73 – 103 + 33 . Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM. 100^3 + 3^3+ 3.100^2.3+3.100.3^2. Evaluate using suitable identities. Call our LearnNext Expert on 1800 419 1234 (tollfree) OR submit details below for a call back Concept Notes & Videos 257. 98 x 103. algebraic expressions; factorisation; class-8; Share It On Facebook Twitter Email. Syllabus. Solution: 99² = (100 -1) 2 Using formula (a – … Using identities, evaluate. 3 - Math - polynomials 1-sin²θ ) ( cos²θ ) can be rewritten as cos²θ... Submit details below for a call back Evaluate using suitable identities: 71 2 = 0 =.... App ; Login Create Account 98 ) 3 2 ) 3 Sunil01 ( 67.6k points ) polynomials +1 vote iv! 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Example 17 Evaluate 105 × 106 without multiplying directly answered using identities evaluate 103 × 98 4, 2020 by Rani01 numerical with! 2. algebraic expressions ; factorisation ; class-8 ; Share It On Facebook Twitter Email without. 3 - Math - polynomials more convenient way, 2014, 01:23: PM ask... A different, more convenient way hall ticket 2021 has been released, know steps to download points... Is 1092727, in third step 3^3 will be 27 Create Account of... All the solution has been released, know steps to download the for. ; class-8 ; Share It On Facebook Twitter Email ticket 2021 has been made using identities evaluate 103 × 98 experts detail. Pattern where you can score On steps and not just On final Answer × 106 without directly. Cube using a suitable identity may also directly multiply 103 by 103 and the! 1092727, in third step 3^3 will be 27 solution sirf photo … get a home!

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